Asked by Zach
solve each equation.
x^4-81=0
x^4-81=0
Answers
Answered by
Reiny
factor it, you are looking at the difference of squares
x^4 - 81 = 0
(x^2 + 9)(x^ - 9) = 0 , and again
(x^2 + 9)(x+3)(x-3)= 0
x= -3 or x = +3 or x^2 = -9 ---> x = ± 3i
If you have not studied complex numbers, then just go with the
x = ± 3
x^4 - 81 = 0
(x^2 + 9)(x^ - 9) = 0 , and again
(x^2 + 9)(x+3)(x-3)= 0
x= -3 or x = +3 or x^2 = -9 ---> x = ± 3i
If you have not studied complex numbers, then just go with the
x = ± 3
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