Asked by Marcy
How would I solve this Equation?
DB = 10log(I/Io)
DB = 10log (140 Io/Io)
DB = 10 log (140)
DB = ?????
This is as far I have gotten on this equation. Can someone please help me finish? I am trying to determine how many times louder than the threshold of sound is from 140 Decibels.
DB = 10log(I/Io)
DB = 10log (140 Io/Io)
DB = 10 log (140)
DB = ?????
This is as far I have gotten on this equation. Can someone please help me finish? I am trying to determine how many times louder than the threshold of sound is from 140 Decibels.
Answers
Answered by
bobpursley
put this in the google search window:
10*log(140)
It is somewhat less than 22 db
10*log(140)
It is somewhat less than 22 db
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