Asked by Brandon
Show that the following numbers are irrational:
1. sqrt3
2. sqrt6
1. sqrt3
2. sqrt6
Answers
Answered by
Mgraph
1. Let sqrt3=m/n where m,n-relatively
primes.
3n^2=m^2 ==>m multiple of 3, m=3k
3n^2=9k^2
n^2=3k^2 ==>n multiple of 3.
primes.
3n^2=m^2 ==>m multiple of 3, m=3k
3n^2=9k^2
n^2=3k^2 ==>n multiple of 3.
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