Asked by Jay
Show that any real numbers a and b and any integers x and y so that x≠ 0, y ≠ 0, x ≠ y and x ≠ -y
(y/x - x/y)((ax+by)/x+y - (ax-by)/x-y) = 2(a -b)
(y/x - x/y)((ax+by)/x+y - (ax-by)/x-y) = 2(a -b)
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Answered by
Homework Dump
(y/x - x/y) * ((ax+by)/(x+y) - (ax-by)/(x-y))
= (y^2-x^2)/(xy) * (2xy)(b-a) / (x^2-y^2)
watch how the factors cancel.
= (y^2-x^2)/(xy) * (2xy)(b-a) / (x^2-y^2)
watch how the factors cancel.
Answered by
Jay
Hello. Thank you for the response! Can you elaborate on how you got the part of (2xy(b-a) / (x^2-y^2)?
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