Question

S is the set of real numbers that are less than 15

Answer 1

5r+8<63

Answer 2

7-3d⪰28

Answer 3

2(3p-11)⪰-16

Answer 4

{1}

Answer 5

{-2,2}

Answer 6

S = {x ∈ ℝ | x < 15}

Answer 7

To solve the inequality 5r + 8 < 63, we can start by isolating the variable r on one side of the inequality.

5r + 8 < 63

Subtracting 8 from both sides:

5r < 55

Next, we can divide both sides of the inequality by 5 to solve for r:

r < 11

Therefore, the solution to the inequality 5r + 8 < 63 is r < 11.

Answer 8

To solve the inequality 7 - 3d ≥ 28, we can start by isolating the variable d on one side of the inequality.

7 - 3d ≥ 28

Subtracting 7 from both sides:

-3d ≥ 21

Next, we can divide both sides of the inequality by -3. When multiplying or dividing both sides of an inequality by a negative number, it is important to remember to reverse the inequality symbol.

d ≤ -7

Therefore, the solution to the inequality 7 - 3d ≥ 28 is d ≤ -7.

Answer 9

To solve the inequality 2(3p-11) ≥ -16, we can start by distributing the 2 to the terms inside the parentheses.

6p - 22 ≥ -16

Next, we can add 22 to both sides of the inequality:

6p ≥ 6

Finally, we divide both sides of the inequality by 6 to solve for p:

p ≥ 1

Therefore, the solution to the inequality 2(3p-11) ≥ -16 is p ≥ 1.

Answer 10

"{1}" represents a set that contains only the element 1.