A bullet moving with a speed 150 m/s strikes a tree and penetrates 3.5 cm before stopping. Find the magnitude of its acceleration and the time taken to stop.

Answer 1

Vf^2 = Vo^2 + 2ad = 0.

(150)^2 + 2a*3.5 = 0,
22500 + 7a = 0,
a = -3214.3m/s^2.

Vf = Vo + at = 0.
Solve for t and get:
t=(Vf-Vo)/a = (0-150) / -3214.3 = 0.0467s.

Answer 2

You didn't convert cm to m

Answer 3

32.14

Answer 4

Wrong

Answer 5

WRONG ANSWER