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A 7.80-g bullet moving at 590 m/s penetrates a tree trunk to a depth of 4.8 cm. Assuming the friction force is constant, determine how much time elapses between the moment the bullet enters the tree and the moment it stops moving.

14 years ago

Answers

NinaCC
Vo=0
7.80g=.0078kg
V=590m/s
d=.048m

W/d
W=Fd
=1/2mV^2 - 1/2m(Vo)^2

13 years ago
NinaCC
Forgot to clarify W/d is the total Force. Where W=KE=1/2mV^2
13 years ago

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