Asked by Jay

A 7.80-g bullet moving at 590 m/s penetrates a tree trunk to a depth of 4.8 cm. Assuming the friction force is constant, determine how much time elapses between the moment the bullet enters the tree and the moment it stops moving.

Answered by NinaCC
Vo=0
7.80g=.0078kg
V=590m/s
d=.048m

W/d
W=Fd
=1/2mV^2 - 1/2m(Vo)^2

Answered by NinaCC
Forgot to clarify W/d is the total Force. Where W=KE=1/2mV^2
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