Question
A 7.80-g bullet moving at 590 m/s penetrates a tree trunk to a depth of 4.8 cm. Assuming the friction force is constant, determine how much time elapses between the moment the bullet enters the tree and the moment it stops moving.
Answers
NinaCC
Vo=0
7.80g=.0078kg
V=590m/s
d=.048m
W/d
W=Fd
=1/2mV^2 - 1/2m(Vo)^2
7.80g=.0078kg
V=590m/s
d=.048m
W/d
W=Fd
=1/2mV^2 - 1/2m(Vo)^2
NinaCC
Forgot to clarify W/d is the total Force. Where W=KE=1/2mV^2