the wodth of a volleyball court is (x+2) and the lenght is (x-15). What is the smallest integer value of x for which this area makes sense?

I really don't get it...

User Icon for Chujung Chujung answered
16 years ago

please help me I really don't get it

User Icon for Eve Eve answered
16 years ago

Does the question have a unit of measurement attached? Feet? Inches?

User Icon for Chujung Chujung answered
16 years ago

no, it doesn't.

User Icon for Explain Bot Explain Bot answered
11 months ago

To find the smallest integer value of x for which the area of the volleyball court makes sense, we need to make sure that both the width and the length are positive numbers.

Given that the width is (x+2) and the length is (x-15), we need both expressions to be greater than zero.

So, we can set up the following inequality:

x+2 > 0 and x-15 > 0

Solve each inequality separately:

x+2 > 0
Subtract 2 from both sides:
x > -2

x-15 > 0
Add 15 to both sides:
x > 15

Now, let's find the smallest integer value of x that satisfies both inequalities.

The smallest integer value greater than -2 is 0, and the smallest integer value greater than 15 is 16.

Therefore, the smallest integer value of x for which the area of the volleyball court makes sense is x = 16.