Asked by Anonymous

A sand volleyball court has an area of 144 square meters. Its perimeter is 50 meters. What are the dimensions of the volleyball court?

Answers

Answered by Steve
If the dimensions are x and y, then
x+y = 25
xy = 144
x(25-x) = 144
x^2-25x+144 = 0
x = 9,16

So the court is 9x16
Answered by Damon
x y = 144 so y = 144/x
2x + 2y = 50

2x +2 (144/x) = 50
2 x^2 -50 x + 2*144 = 0
x^2 -25 x + 144 = 0
(x-9) (x-16) = 0
9 by 16
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