Asked by JRoussel
Consider the standard cell at 25C based on the following half-reactions. Pb^2+ + 2e^- --> Pb E=-0.13V Zn^2+ + 2e^- --> Zn E=-0.76V To the standard cell, OH-, is added to the zinc compartment causing precipitation of Zn(OH)2. After precipitation is complete, the concentration of the OH- is 0.10M and the measured cell potential is 1.05V. calculate the Ksp value for Zn(OH)2(s) Zn(OH)2-> Zn^2+(aq) + OH-(aq) Ksp=?
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