Asked by Chemistry question.
What would the standard cell potential in volts be for
Mn(s) + 2Ce4+(aq) -> Mn2+(aq) + 2Ce3+(aq)?
Mn(s) + 2Ce4+(aq) -> Mn2+(aq) + 2Ce3+(aq)?
Answers
Answered by
DrBob222
We don't do homework but we can help you understand. What about the problem do you not understand? Do you know to look up the cell potential for the Mn to Mn^+2 and add it to the cell potential for the Ce^+4 ==>Ce^+3?
That should give you the cell potential for the reaction. Post your work if you get stuck.
That should give you the cell potential for the reaction. Post your work if you get stuck.
Answered by
Sonny
The two values I got for those cell potentials were 1.61 (Ce^4+ + 2e- -> Ce^3+) and -1.18 for Mn^2+ + 2e^- -> Mn. Which equals 0.43V.
I wasn't sure if I double the value for Ce^4 ... as they have 2's at front of them?
I wasn't sure if I double the value for Ce^4 ... as they have 2's at front of them?
Answered by
DrBob222
No, you do not double the value for Ce^+4. Sorry it took me so long to get back to you.
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