Question

What would the standard cell potential in volts be for

Mn(s) + 2Ce4+(aq) -> Mn2+(aq) + 2Ce3+(aq)?

Answer 1

We don't do homework but we can help you understand. What about the problem do you not understand? Do you know to look up the cell potential for the Mn to Mn^+2 and add it to the cell potential for the Ce^+4 ==>Ce^+3?
That should give you the cell potential for the reaction. Post your work if you get stuck.

Answer 2

The two values I got for those cell potentials were 1.61 (Ce^4+ + 2e- -> Ce^3+) and -1.18 for Mn^2+ + 2e^- -> Mn. Which equals 0.43V.

I wasn't sure if I double the value for Ce^4 ... as they have 2's at front of them?

Answer 3

No, you do not double the value for Ce^+4. Sorry it took me so long to get back to you.