Asked by m

how much energy is released when a 5600 gram sample of water cools from 99 degress celsius to 28 degrees celcius
Answered by DrBob222
Note the correct spelling of celsius.
q = mass x specific heat x delta T.
q = 5600 g x 4.184 J/g*C x (99-28)
Answered by Anonymous
Dsgd
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