Asked by Amanda
How much energy is released when a 5600-g sample of water cools from 99 degrees C to 28 degrees C. The specific heat capacity of water is 4.18 J/(g*degrees C)
Can someone please tell me the steps to do this?
Can someone please tell me the steps to do this?
Answers
Answered by
bobpursley
heatlost= masswater*specificheatcapacity*changeinTemp
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