Asked by Anonymous
If an aqueous solution of sulfuric acid (H2SO4) is neutralized by 3.20 mol of sodium hydroxide (NaOH), how many moles of acid were originally present in the solution?
Answers
Answered by
DrBob222
If completely neutralized, the balanced equation is
2NaOH + H2SO4 ==> Na2SO4 + 2H2O
The equation tell you that 2 moles NaOH = 1 mole H2SO4 so 3.2 moles NaOH must equal ?? moles H2SO4.
2NaOH + H2SO4 ==> Na2SO4 + 2H2O
The equation tell you that 2 moles NaOH = 1 mole H2SO4 so 3.2 moles NaOH must equal ?? moles H2SO4.
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