Asked by Eleanya
an aqueous solution contains 1.00g/L of a derivative of detergent lauryl alcohol.the osmotic pressure of this solution at 25 °c is 2.0 x 10³ Nm-², what is the molar mass of the detergent.
Answers
Answered by
DrBob222
2000 N/m^2 = 2000 pascals.
Convert to atmospheres 2000/101325 = approx 0.02 but that's an estimate.
Then pi = MRT
You know pi, R, T, solve for M = molarity.
Then M = mols/L. You know M and L, solve for mols.
Then mol = grams/molar mass. You know mols and grams, solve for molar mass.
Post your work if you get stuck.
Convert to atmospheres 2000/101325 = approx 0.02 but that's an estimate.
Then pi = MRT
You know pi, R, T, solve for M = molarity.
Then M = mols/L. You know M and L, solve for mols.
Then mol = grams/molar mass. You know mols and grams, solve for molar mass.
Post your work if you get stuck.
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