Asked by samuel
Light falls on a photoelectric surface that has a work function of 2.90 eV. If the voltage required to stop the ejected electrons is 0.210 V, what is the wavelength of the incident radiation?
Answers
Answered by
drwls
The energy provided by a photon is
e*(Work function) + e*(stopping voltage)
= (1.602*10^-19 C)*(3.11 J/C)
= 4.98*10^-19 joules
Set that equal to h*c/(wavelength) and solve for wavelength.
Wavelength = 6.62*10^-34*3.00*10^8/4.98*10^-19
= 3.99*10^-7 m = 399 nanometers (violet)
e*(Work function) + e*(stopping voltage)
= (1.602*10^-19 C)*(3.11 J/C)
= 4.98*10^-19 joules
Set that equal to h*c/(wavelength) and solve for wavelength.
Wavelength = 6.62*10^-34*3.00*10^8/4.98*10^-19
= 3.99*10^-7 m = 399 nanometers (violet)
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