Asked by Angel
Light falls on a double slit with slit separation
of 2.19 × 10
−6 m, and the first bright fringe is
seen at an angle of 12.7
◦
relative to the central
maximum.
What is the wavelength of the light?
Answer in units of nm
of 2.19 × 10
−6 m, and the first bright fringe is
seen at an angle of 12.7
◦
relative to the central
maximum.
What is the wavelength of the light?
Answer in units of nm
Answers
Answered by
Elena
λ = d• tanα = 2.19•10^-6 • 0.225 =4.94 •10^-7 m = 494 nm
Answered by
Angel
It says incorrect. Can you explain the process?
Answered by
Elena
The coordinate of the k-maximum (separation between the central and the first maxima) is
x(max) = k•λ•L/d,
where L is the separation between the slits and the screen, d is the separation between the slits.
Now, imagine the triangle : the midpoint between slits (taking into account that the slits are very close to each other, this point is the slit), the central maximum on the screen, and the first bright fringe. In this triangle
tan α = x(1max)/L
x(1max) = L •tan α
Then for k=1
x(1max) = λ•L/d,
L •tan α =λ•L/d,
tan α = λ/d,
x(max) = k•λ•L/d,
where L is the separation between the slits and the screen, d is the separation between the slits.
Now, imagine the triangle : the midpoint between slits (taking into account that the slits are very close to each other, this point is the slit), the central maximum on the screen, and the first bright fringe. In this triangle
tan α = x(1max)/L
x(1max) = L •tan α
Then for k=1
x(1max) = λ•L/d,
L •tan α =λ•L/d,
tan α = λ/d,
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.