Asked by Chris
What is the molarity and normality of 100.3 grams of calcium hydroxide dissolved in 775 ml of water?
Answers
Answered by
DrBob222
Technically one can't answer this question. Why? Because 100.3 g Ca(OH)2 added to 775 mL water will be more than 775 mL of solution. The definition of M and N is based on th final solution, not on how much water is added. The question should ask, What is......in 775 mL of SOLUTION. I will assume it is 775 mL of solution and not 775 mL water + the solid Ca(OH)2.
molar mass Ca(OH)2 = 74.09
moles Ca(OH)2 = 100.3/74.09 = ??
equivalent mass Ca(OH)2 = 75.09/2 (for the two OH ions attached.)
equivalents Ca(OH)2 = 100.3/37.54 = ??
M = moles/L soln
N = equivalents/L soln.
molar mass Ca(OH)2 = 74.09
moles Ca(OH)2 = 100.3/74.09 = ??
equivalent mass Ca(OH)2 = 75.09/2 (for the two OH ions attached.)
equivalents Ca(OH)2 = 100.3/37.54 = ??
M = moles/L soln
N = equivalents/L soln.
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