Question

A small electric motor is used to lift a
0.50-kilogram mass at constant speed. If the
mass is lifted a vertical distance of 1.5 meters in
5.0 seconds, the average power developed by the
motor is

Answer 1

change in potential energy = m g h

energy/time = power = m g h /t

= .50 * 9.81 * 1.5 / 5

Joules/second or Watts

Answer 2

calculate the power out in watts and horse power of an 80 kg man that climbs a flight of stairs 5.8m high in 4.0s.