Asked by Cassidy
                a bag contains 6 red marbles and 2 blue marbles. what is the probability of chosing a red marble and a blue marble at the same time?
            
            
        Answers
                    Answered by
            drwls
            
    P(red, then blue) + P(blue, then red)
(6/8)*(2/7) + (2/8)*(6/7) = 24/56 = 3/7
    
(6/8)*(2/7) + (2/8)*(6/7) = 24/56 = 3/7
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