Asked by Lucy
Find the concentration of H3O if the pOH of a solution is 11.700:
So far I have: pH= 14.000- pOH which is 14.000-11.700=2.300
pH = -log[H3)]
-2.300 = log[H3O]
Lost after that!!!
Help please.
So far I have: pH= 14.000- pOH which is 14.000-11.700=2.300
pH = -log[H3)]
-2.300 = log[H3O]
Lost after that!!!
Help please.
Answers
Answered by
DrBob222
You're almost there.
log(H3O^+) = -2.3
Set -2.3 up on your calculator. Press the 10<sup>x</sup> key. And the answer comes out. You should get 0.00501 or 5 x 10<sup>-3</sup> depending upon how you have your calculator set up to display the answer.
log(H3O^+) = -2.3
Set -2.3 up on your calculator. Press the 10<sup>x</sup> key. And the answer comes out. You should get 0.00501 or 5 x 10<sup>-3</sup> depending upon how you have your calculator set up to display the answer.
Answered by
Lucy
Thanks a lot. I just couldn't get there.