Question
An outfielder throws a 0.150 kg baseball at a speed of 26.0 m/s and an initial angle of 30.0°. What is the kinetic energy of the ball at the highest point of its motion?
Answers
John
m = .150kg
v = 40m/s
Theta = 30 degrees
Vh = 40*cos(30)>>>>Vh = 34.64m/s
KE = (1/2)(.150kg)(34.64)^2>>>>KE = 90J
v = 40m/s
Theta = 30 degrees
Vh = 40*cos(30)>>>>Vh = 34.64m/s
KE = (1/2)(.150kg)(34.64)^2>>>>KE = 90J