Asked by Anonymous

The cloth shroud from around a mummy is found to have a carbon-14 activity of 8.1 disintegrations per minute per gram of carbon as compared with living organisms that undergo 15.2 disintegrations per minute per gram of carbon.

From the half-life for carbon-14 decay, 5715 yr, calculate the age of the shroud.

Answers

Answered by DrBob222
k = 0.693/t<sub>1/2</sub>
k = 0.693/5715yr = 1.213E-4
Substitute k into the below equation.
ln(No/N) = kt
No = 15.2
N = 8.1
k from above.
Solve for t (in years).
Answered by Anonymous
Thanks.
Answered by Anonymous
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