Question
THE AMOUNT OF CLOTH USED TO MAKE FOUR CURTAINS IS GIVEN BY THE FUNCTION A=-4X^2 + 40X WHERE X IS THE WIDTH OF ONE CURTAIN IN FEET AND a IS THE TOTAL AREA IN SQUARE FEET. FIND THE WIDTH THAT MAXIMIZES THE AREA OF THE CURTAINS. WHAT IS THE MAXIMUM AREA?
Answers
this problem consists of finding the vertex of the parabola,
the x of the vertex is -b/(2a) = -40/-8 = 5
when x = 5
A = -4(25) + 40(5) = 100
So the maximum area is 100 ft^2 , when the width is 5 ft.
I would suggest you have your caps lock fixed on your keyboard, it will be so much easier to read your post.
the x of the vertex is -b/(2a) = -40/-8 = 5
when x = 5
A = -4(25) + 40(5) = 100
So the maximum area is 100 ft^2 , when the width is 5 ft.
I would suggest you have your caps lock fixed on your keyboard, it will be so much easier to read your post.
A=-4x^2+40x
By completing the square
A= -4(x^2-10x+25)+100
A= -4(x-5)^2+100
Vertex is (5,100)
Max is 100 ft
By completing the square
A= -4(x^2-10x+25)+100
A= -4(x-5)^2+100
Vertex is (5,100)
Max is 100 ft
I do not know