Asked by noell
Evaluate the Integral
∫1, 0 x^3(1+x^4)^6dx where 1=b 0=a for the limits
∫1, 0 x^3(1+x^4)^6dx where 1=b 0=a for the limits
Answers
Answered by
MathMate
use substitution
u=1+x^4
du = 4x^3dx
du/4 = x^3dx
so
∫x^3(1+x^4)^6dx
=(1/4)∫du/u^6
Use the power rule to integrate and evaluate between limits.
u=1+x^4
du = 4x^3dx
du/4 = x^3dx
so
∫x^3(1+x^4)^6dx
=(1/4)∫du/u^6
Use the power rule to integrate and evaluate between limits.
There are no AI answers yet. The ability to request AI answers is coming soon!