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Question

Evaluate the integral
∫ x/(x+1)^2+4 dx
13 years ago

Answers

use partial fractions:
x/(x+1)^2 + 4
= 1/(x+1) - 1/(x+1)^2 + 4

Integral is just

ln(x+1) + 1/(x+1) + 4x

13 years ago

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