Asked by elizabeth

Marcus flips a coin and tosses a six-sided die with the sides numbered 1-6. What is the probaility that he gets a head on the coin and a number divisible by 3 on the die?
Answered by Anonymous
A six-sided die with sides numbered 1 through 6 is tossed twice. What is the probability of getting a number larger than 4 on both throws?
Answered by tom
1/9
Answered by Damon
Elizabeth:
3 and 6 are divisible by 3 so 2/6 = 1/3
1/2 *1/3 = 1/6
Anon:
5 or 6/ 6
1/3 each time
independent tosses so
1/3 * 1/3 = 1/9
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