Asked by Tara
Water is being pumped at a 3 cubic feet/minute into a cylindrical storage tank with a circular base of a radius 4 feet. Find the depth of the water (d) as a fucntion of time (t)
Answers
Answered by
bobpursley
volume= dV/dt*time
PIr^2 h= dV/dt*time
solve for h, given dV/dt= 3ft^3 /min
PIr^2 h= dV/dt*time
solve for h, given dV/dt= 3ft^3 /min
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