Asked by Anonymous
A buffer that consists of a mixture of NaH2PO4 and K2HPO4 has a pH of 6.73. The (HPO4)/(H2PO4) ratio in this buffer is what? If (k1,k2,and k3 for H3PO4 are 7.1x10^-3, 6.2x10^-8, and 4.5x10^-13 respectively)
Answers
Answered by
DrBob222
Substitute the pH and pKa into
pH = pKa + log(base)/(acid) and solve for the ratio of (base)/(acid).
pH = pKa + log(base)/(acid) and solve for the ratio of (base)/(acid).
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