Asked by Nevaeh
I got pH = 5.3
A 1.00 L buffer solution is 0.250 M in HC2H3O2 and 0.250 M in NaC2H3O2. Calculate the pH of the solution after the addition of 0.150 mol of solid NaOH. Assume no volume change upon the Additon o f NaOH. The Ka value for HC2H3O2 at 25 C is 1.8 x 10^-5.
Chemistry-Dr.Bob222 - DrBob222, Friday, April 29, 2016 at 2:38pm
HC2H3O2 = HAc
NaC2H3O2 = NaAc
millimols HAc = mL x M = approx 250
mmols NaAc = 250
0.150 mol NaOH = 150 mmol
......HAc + OH^- ==> Ac^- + H2O
I.....250....0.......250.......
add........150.................
C...-150..-150.......+150
E.....100...0........400
Plug the E line into the HH equation and solve for pH.
A 1.00 L buffer solution is 0.250 M in HC2H3O2 and 0.250 M in NaC2H3O2. Calculate the pH of the solution after the addition of 0.150 mol of solid NaOH. Assume no volume change upon the Additon o f NaOH. The Ka value for HC2H3O2 at 25 C is 1.8 x 10^-5.
Chemistry-Dr.Bob222 - DrBob222, Friday, April 29, 2016 at 2:38pm
HC2H3O2 = HAc
NaC2H3O2 = NaAc
millimols HAc = mL x M = approx 250
mmols NaAc = 250
0.150 mol NaOH = 150 mmol
......HAc + OH^- ==> Ac^- + H2O
I.....250....0.......250.......
add........150.................
C...-150..-150.......+150
E.....100...0........400
Plug the E line into the HH equation and solve for pH.
Answers
Answered by
DrBob222
That's ok but I believe you are allowed another significant figure. That 5 comes from the log. I obtained 5.34.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.