Asked by lilly
what is the molarity of a solution containing 23g of NaCl in 500 mL of solution? (the molecular mass of NaCl is 58.44.)
Answers
Answered by
tina
molarity = moles solute / L solution
Convert g to moles:
23g NaCL x 1 mol/58.44 g NacL = 0.394 mol
Convert ML to Liter:
500 mL x 1 L /1000 mL = 0.5 L
Therefore...
M= 0.394 mol/0.5L = 0.788 Molarity.. should be the right answer
Convert g to moles:
23g NaCL x 1 mol/58.44 g NacL = 0.394 mol
Convert ML to Liter:
500 mL x 1 L /1000 mL = 0.5 L
Therefore...
M= 0.394 mol/0.5L = 0.788 Molarity.. should be the right answer
Answered by
T gupta
No of moles = mass / molar mass
= 5.85/58.5
= 0.1 miles
Molarity = no of moles / volume
= 0.1/500 ×1000
= 0.2 M ANSWER
= 5.85/58.5
= 0.1 miles
Molarity = no of moles / volume
= 0.1/500 ×1000
= 0.2 M ANSWER
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