Asked by Jamie

What is the molarity of a solution made by dissolving 32.654 g of aluminum sulfate, Al2(SO4)3, in water and diluting with water to 125.0 mL total?
Answered by DrBob222
M = mols/L.
mols Al2(SO4)3 = g Al2(SO4)3/molar mass Al2(SO4)3 and L = 0.125.
Answered by Anonymous
.241 M
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