Question
Find the minimum kinetic energy needed for a 3.7×104-kg rocket to escape the Moon.
Answers
drwls
G*M(rocket)*M(moon)/R(moon)
where G is the universal gravity constant.
It can also be written
M(rocket)*g'(moon)*R(moon)
where g' is the acceleration of gravity at the Moon's surface. It is about g/6, or 1.6 m/s^2.
where G is the universal gravity constant.
It can also be written
M(rocket)*g'(moon)*R(moon)
where g' is the acceleration of gravity at the Moon's surface. It is about g/6, or 1.6 m/s^2.