Find the minimum kinetic energy needed for a 3.7×104-kg rocket to escape the Moon.

Answer 1

G*M(rocket)*M(moon)/R(moon)

where G is the universal gravity constant.

It can also be written

M(rocket)*g'(moon)*R(moon)

where g' is the acceleration of gravity at the Moon's surface. It is about g/6, or 1.6 m/s^2.