Asked by Chris
Verify the equation is an identitiy:
cot(x)tan(x+pi) - sin(pi-x)cos((pi/2)-x) = cos^2x
Thanks
cot(x)tan(x+pi) - sin(pi-x)cos((pi/2)-x) = cos^2x
Thanks
Answers
Answered by
Mgraph
tan(x+pi)=tan(x)
sin(pi-x)=sin(x)
cos(pi/2-x)=sin(x)
cot(x)tan(x)=1
1-sin^2(x)=cos^2(x)
sin(pi-x)=sin(x)
cos(pi/2-x)=sin(x)
cot(x)tan(x)=1
1-sin^2(x)=cos^2(x)
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