Asked by H.T
Hypothetically, if you were standing on the balcony of an apartment on the 10th level of building and you throw a ball at 30° above the horizontal away from the building at 4.5m/s, how far from the building would the ball land?. The height from which the ball is thrown is approximately 30m.
Answers
Answered by
bobpursley
Hypothetically, do you ignore wind and air resistance?
Initial vertical velocity: 4.5sin30
go to the height equation:
hf=hi+InitialVelocityvertical*t-1/2 g t^2
hf=-30, hi=0 solve for time in air, t.
distance equation
horizonaldistance= 4.5cos30*timeinair
Hypothetically, with no air friction or force.
Initial vertical velocity: 4.5sin30
go to the height equation:
hf=hi+InitialVelocityvertical*t-1/2 g t^2
hf=-30, hi=0 solve for time in air, t.
distance equation
horizonaldistance= 4.5cos30*timeinair
Hypothetically, with no air friction or force.
Answered by
Jeff
First of all your initial vertical velocity is not 4.5 m/s.
it is Viy= 4.5 * sin(30)
and your horizontal = 4.5 * cos(30)
it is Viy= 4.5 * sin(30)
and your horizontal = 4.5 * cos(30)
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