No green? that means
Pr(6/8)*(5/7)(4/6)
check my thinking. There are initially six non green, our of 8 marbles, then there are 5 out of 7, and on the third draw, 4 of 6 are non green.
There are many harder ways to do this.
A bowl contains 8 marbles:
3 red, 2 blue, 1 white, and 2 green. If 3 marbles are randomly selected without replacement, what is the probability that no green marble is selected?
I don't know how to do probability.
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