Question
14, -9 write a quadratic equation with these solutions. With 1 being there greatest common factor
Answers
Anonymous
a*x^2+bx+c=a*(x-x1)*(-x2)
Where is x1 and x2 roots of equation
In your case a=1 so:
x^2+bx+c=(x-x1)*(x-x2)=
(x-14)*[x-(-9)]=
(x-14)*(x+9)=
x*x-x*14+9*x-9*14=
x^2-14x+9x-126=
x^2-5x-126
Where is x1 and x2 roots of equation
In your case a=1 so:
x^2+bx+c=(x-x1)*(x-x2)=
(x-14)*[x-(-9)]=
(x-14)*(x+9)=
x*x-x*14+9*x-9*14=
x^2-14x+9x-126=
x^2-5x-126