Asked by Mistaking
                how do I solve quadratic equations by elimination?
eg: 6x^2-3x=2y-5
2x^2+x=y-4
            
            
        eg: 6x^2-3x=2y-5
2x^2+x=y-4
Answers
                    Answered by
            Steve
            
    6x^2-3x-2y = -5
4x^2+2x-2y = -8
now subtract to get
2x^2-5x = 3
2x^2-5x-3 = 0
(2x+1)(x-3) = 0
...
    
4x^2+2x-2y = -8
now subtract to get
2x^2-5x = 3
2x^2-5x-3 = 0
(2x+1)(x-3) = 0
...
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.