Asked by Mistaking
how do I solve quadratic equations by elimination?
eg: 6x^2-3x=2y-5
2x^2+x=y-4
eg: 6x^2-3x=2y-5
2x^2+x=y-4
Answers
Answered by
Steve
6x^2-3x-2y = -5
4x^2+2x-2y = -8
now subtract to get
2x^2-5x = 3
2x^2-5x-3 = 0
(2x+1)(x-3) = 0
...
4x^2+2x-2y = -8
now subtract to get
2x^2-5x = 3
2x^2-5x-3 = 0
(2x+1)(x-3) = 0
...
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.