Asked by Sarah
A 0.225g sample of a weak monoprotic acid requires 37.50 mL of 0.100 M NaOH solution to reach the equivalence point. What is the molar mass of the acid?
Answers
Answered by
DrBob222
HA + NaOH ==> NaA + H2O
moles NaOH added = M x L = ??
moles HA must be the same (see the coefficients in the balanced equation).
moles HA = grams/molar mass
You know moles HA and grams HA, solve for molar mass.
moles NaOH added = M x L = ??
moles HA must be the same (see the coefficients in the balanced equation).
moles HA = grams/molar mass
You know moles HA and grams HA, solve for molar mass.
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