Asked by mary
Rhombus ABCD has an area of 264 square units. If DB=12 units find AC.
So far this is what I have-
1/2(264)=132 132/2=66
66-12=44units
Is this the correct process?
So far this is what I have-
1/2(264)=132 132/2=66
66-12=44units
Is this the correct process?
Answers
Answered by
bobpursley
I don't follow your work.
Sketch the rhombas. One diagonal is 12, so half that diagonal is 6.
call that half b, so 2b=12
now call half the other diagonal a
so the length of that diagonal is 2a, and that is what you are looking for.
Now, the diagonals of a rhombus are perpendicular bisectors, so you have four right triangles, the area of which is
1/2 a b=264/4
or ab=132, but a=6, so a=22
which means 2a=44, so your answer is correct.
Sketch the rhombas. One diagonal is 12, so half that diagonal is 6.
call that half b, so 2b=12
now call half the other diagonal a
so the length of that diagonal is 2a, and that is what you are looking for.
Now, the diagonals of a rhombus are perpendicular bisectors, so you have four right triangles, the area of which is
1/2 a b=264/4
or ab=132, but a=6, so a=22
which means 2a=44, so your answer is correct.
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