Asked by Anonymous

In a rhombus ABCD, m∠A = 31°. Point O is a point of intersection of diagonals. Find the measures of the angles of triangle ΔBOC.

I got 15.5 degrees for angle OCB and thats right all I need is the angles for OBC and BOC
Answered by Steve
note that ΔBOC is a right triangle, since the diagonals are perpendicular.
Answered by THATGUY260
<BOC = 90
<OBC = 74.5
Answered by Anonymous
why does everyone keep getting BOC=90?
that is wrong.
Answered by Why do you care?
m∠BOC = 90 degrees
, m∠OCB = 15.5 degrees
, m∠OBC = 74.5 degrees
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