Asked by Jules
Im stuck on this question. Could someone answer it so I understand it.Thanks
When (R)-Butan-z-ol is treated with TsCl in pyridine and the tosylated alcohol is treated with sodium iodide in acetone, the resulting product is?
A)(R)-2-iodobutane
B)(S)-iodobutane
C)2-iodobutane
D)1-butene
E)None of these
When (R)-Butan-z-ol is treated with TsCl in pyridine and the tosylated alcohol is treated with sodium iodide in acetone, the resulting product is?
A)(R)-2-iodobutane
B)(S)-iodobutane
C)2-iodobutane
D)1-butene
E)None of these
Answers
Answered by
Dr Jeff
The alcohol of the 2-butanol will be converted to the tosylate (xxx.mhhe_com/physsci/chemistry/carey5e/Ch08/ch8-10-1_html) with no change is sterochemistry. Now the iodide does an SN2 displacement flipping over the substituents about the 2-carbon. It will now be (S)-2-iodobutane. xxx = w etc. _ =.
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