Question

I"m stuck on this question
"Rays PQ and QR ae perpendicular.Point S lies in the interior of angle PQR.If angle PQS!=4+7a and angle SQR=9+4a,find angle PQS and angle SQR.
PLEASE HELP!!!!

Answer 1

4 + 7 a + 9 + 4 a = 90 degrees
13 + 11 a = 90
11 a = 77
a = 7

PQS = 4 + 49
SQR = 9 + 28

Answer 2

Thank you so much!!!!!