P = 2L + 2W
P = (2 * 8) + (2 * 6)
P = 16 + 12
P = 28
A = L * W
A = 6 * 8
A = 48 sq. inches
Determine the perimeter and area of a rectangle that has a width of 6 inches and a length of 8 inches.
Using a ratio of 1:2, draw a similar rectangle that is double the width and length of the first shape. Determine the perimeter and area of this new rectangle.
Draw one more rectangle using a ratio of 1:3 (a rectangle that is triple the width and length of the original shape).
3 answers
Thank you so much. I got that part but I don't understand using the ratio 1:2.
Perimeter of rectangle:
P=2w+2l
P=2(w+l)
Area of rectangle:
A=w*l
w=width
l=length
w=6in l=8in
P=2(w+l)
P=2*(6+8)=2*14=28in
A=w*l=6*8=48in^2
Ratio 1:2
w=2*6=12in l=2*8=16in
P=2(w+l)
P=2*(12+16)=2*28=56in
A=w*l=12*16=192in^2
Ratio 1:3
w=3*6=18in l=3*8=24in
P=2(w+l)
P=2*(18+24)=2*42=84in
A=w*l=18*24=432in^2
P=2w+2l
P=2(w+l)
Area of rectangle:
A=w*l
w=width
l=length
w=6in l=8in
P=2(w+l)
P=2*(6+8)=2*14=28in
A=w*l=6*8=48in^2
Ratio 1:2
w=2*6=12in l=2*8=16in
P=2(w+l)
P=2*(12+16)=2*28=56in
A=w*l=12*16=192in^2
Ratio 1:3
w=3*6=18in l=3*8=24in
P=2(w+l)
P=2*(18+24)=2*42=84in
A=w*l=18*24=432in^2
1 answer