Asked by Wendy A.

An 8.5 x 10^2 elevator is pulled up at a constant velocity of 1 m/s by a 10 kW motor. Calculate the efficiency of the motor.
Answered by bobpursley
power in work= mgh/t=8.5E2*9.8*1m/s=about 5000 watts

Efficiencey appx= 5000/10K aboaut 50 percent.

check that.
Answered by drwls
You have to provide dimensions along with the 850 for the elevator.

M g V is the power delivered.

Divide that by 10,000 W for the efficiency
Answered by Wendy A.
Ok thanks to both for the answers!
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