Asked by J
A 22 kg suitcase is being pulled with constant speed by a handle that is at an angle of 23 ∘ above the horizontal.
If the normal force exerted on the suitcase is 150 N , what is the force F applied to the handle?
I don't understand how the equations are suppose to be manipulated. Please help
If the normal force exerted on the suitcase is 150 N , what is the force F applied to the handle?
I don't understand how the equations are suppose to be manipulated. Please help
Answers
Answered by
bobpursley
I assume you mean by "the normal force" the force the floor is exerting.
Normal force=weight-forcepulling up
= mass*9.8N/kg - F*sin23=150N
F=(mass*9.8-150)/sin23 deg
Normal force=weight-forcepulling up
= mass*9.8N/kg - F*sin23=150N
F=(mass*9.8-150)/sin23 deg
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