Asked by Emily
The product of two numbers is 108, and the quotient is 12. What are the two numbers.
Answers
Answered by
Bosnian
a=first number
b=second number
a*b=108 Divide with b
a=108/b
a/b=12
(108/b)/b=12
108/b^2=12
108=12*b^2 Divide with 12
9=b^2
b=sqroot(9)
b=3
a=108/b
a=108/3
a=36
a=36 b=3
a*b=36*3=108
a/b=36/3=12
b=second number
a*b=108 Divide with b
a=108/b
a/b=12
(108/b)/b=12
108/b^2=12
108=12*b^2 Divide with 12
9=b^2
b=sqroot(9)
b=3
a=108/b
a=108/3
a=36
a=36 b=3
a*b=36*3=108
a/b=36/3=12
Answered by
Bosnian
You also can write:
b=sqroot(9)
b= -3
a=108/b
a=108/ -3
a= -36
a= -36 b= -3
a*b=(-36)*(-3)=108
a/b= -36/ -3=12
b=sqroot(9)
b= -3
a=108/b
a=108/ -3
a= -36
a= -36 b= -3
a*b=(-36)*(-3)=108
a/b= -36/ -3=12
Answered by
Bosnian
sqroot(9)= 3 OR -3
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