(T1 - T2) = I*alpha = (1/2)M*R^2*(a/R)
(1/2) M*a.
I agree with you. M is the pulley mass.
You need the accleration of the masses, a.
That equals the angular acceleration (which you say you have got by doing b), multiplied by R.
The system shown below is released from rest. The mb = 35 kg block is 2 m above the ledge. The pulley is a uniform disk with a radius of 10 cm and mass M = 5.0 kg. Assume that the string does not slip on the pulley.
(a) Find the speed of the 35 kg block just before it hits the ledge.
(b) Find the angular speed of the pulley at that time.
(c) Find the tensions in the strings.
I having trouble with this part I was able to get part a and b.
I suppose to use T1-T2=(1/2*M)a
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