Asked by Lu
find the slope of the tangent line
y= -5x^1/2 + X^3/2; X=25
y= -5x^1/2 + X^3/2; X=25
Answers
Answered by
Reiny
dy/dx = (-5/2)x^(-1/2) + (3/2)x^(1/2)
= -5/(2√x) + 3√x/2
when x = 25
y = -5(√25) + (√25)^3 = -25 + 125 = 100
dy/dx = -5/(2√25) + 3√25/2 = -1/2 + 15/2 = 7
then
(y-100) = 7(x-25)
Finish it up to express the final equation is the form you want.
= -5/(2√x) + 3√x/2
when x = 25
y = -5(√25) + (√25)^3 = -25 + 125 = 100
dy/dx = -5/(2√25) + 3√25/2 = -1/2 + 15/2 = 7
then
(y-100) = 7(x-25)
Finish it up to express the final equation is the form you want.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.