Question
Four particles, one at each of the four corners of a square with 2.5-m-long edges, are connected by mass less rods. The masses of the particles are m1 = m3 = 2.0 kg and m2 = m4 = 7.0 kg. Find the moment of inertia of the system about the z axis.
Answers
Equation: I=M*L^2
M is the mass of the object.
I is the moment of inertia.
L is the length squared or radius squared.
I=(2.5^2(m2+m1))+ (2.5^2(m2+m3))
I= 6.25*(9)+6.25*(9)
I=112.5 kg*m^2
M is the mass of the object.
I is the moment of inertia.
L is the length squared or radius squared.
I=(2.5^2(m2+m1))+ (2.5^2(m2+m3))
I= 6.25*(9)+6.25*(9)
I=112.5 kg*m^2
Related Questions
Consider a square of side length a = 9.7 cm with charged particles at each of the corners. Three of...
a box is to be made by cutting out the corners of a square piece of cardboard and folding the edges...
Four charged particles are arranged at the corners (1, 2, 3 and 4) of a square with each side length...