Asked by Kayla
Four particles, one at each of the four corners of a square with 2.5-m-long edges, are connected by mass less rods. The masses of the particles are m1 = m3 = 2.0 kg and m2 = m4 = 7.0 kg. Find the moment of inertia of the system about the z axis.
Answers
Answered by
Kayla
Equation: I=M*L^2
M is the mass of the object.
I is the moment of inertia.
L is the length squared or radius squared.
I=(2.5^2(m2+m1))+ (2.5^2(m2+m3))
I= 6.25*(9)+6.25*(9)
I=112.5 kg*m^2
M is the mass of the object.
I is the moment of inertia.
L is the length squared or radius squared.
I=(2.5^2(m2+m1))+ (2.5^2(m2+m3))
I= 6.25*(9)+6.25*(9)
I=112.5 kg*m^2
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